Rename Aliases.hs to BigFloat.hs, now containing numeric-prelude instances for BigFloats.

[numerical-analysis.git] / src / Roots / Simple.hs

{-# LANGUAGE RebindableSyntax #-}

-- | The Roots.Simple module contains root-finding algorithms. That
--   is, procedures to (numerically) find solutions to the equation,
--
--   > f(x) = 0
--
--   where f is assumed to be continuous on the interval of interest.
--

module Roots.Simple
where

import Data.List (find)

import Normed

import qualified Roots.Fast as F

import NumericPrelude hiding (abs)
import Algebra.Absolute
import Algebra.Field
import Algebra.Ring

-- | Does the (continuous) function @f@ have a root on the interval
--   [a,b]? If f(a) <] 0 and f(b) ]> 0, we know that there's a root in
--   [a,b] by the intermediate value theorem. Likewise when f(a) >= 0
--   and f(b) <= 0.
--
--   Examples:
--
--   >>> let f x = x**3
--   >>> has_root f (-1) 1 Nothing
--   True
--
--   This fails if we don't specify an @epsilon@, because cos(-2) ==
--   cos(2) doesn't imply that there's a root on [-2,2].
--
--   >>> has_root cos (-2) 2 Nothing
--   False
--   >>> has_root cos (-2) 2 (Just 0.001)
--   True
--
has_root :: (Algebra.Field.C a,
             Ord a,
             Algebra.Ring.C b,
             Algebra.Absolute.C b,
             Ord b)
         => (a -> b) -- ^ The function @f@
         -> a       -- ^ The \"left\" endpoint, @a@
         -> a       -- ^ The \"right\" endpoint, @b@
         -> Maybe a -- ^ The size of the smallest subinterval
                   --   we'll examine, @epsilon@
         -> Bool
has_root f a b epsilon =
  F.has_root f a b epsilon Nothing Nothing


-- | We are given a function @f@ and an interval [a,b]. The bisection
--   method checks finds a root by splitting [a,b] in half repeatedly.
--
--   If one is found within some prescribed tolerance @epsilon@, it is
--   returned. Otherwise, the interval [a,b] is split into two
--   subintervals [a,c] and [c,b] of equal length which are then both
--   checked via the same process.
--
--   Returns 'Just' the value x for which f(x) == 0 if one is found,
--   or Nothing if one of the preconditions is violated.
--
--   Examples:
--
--   >>> bisect cos 1 2 0.001
--   Just 1.5712890625
--
--   >>> bisect sin (-1) 1 0.001
--   Just 0.0
--
bisect :: (Algebra.Field.C a,
           Ord a,
           Algebra.Ring.C b,
           Algebra.Absolute.C b,
           Ord b)
       => (a -> b) -- ^ The function @f@ whose root we seek
       -> a       -- ^ The \"left\" endpoint of the interval, @a@
       -> a       -- ^ The \"right\" endpoint of the interval, @b@
       -> a       -- ^ The tolerance, @epsilon@
       -> Maybe a
bisect f a b epsilon =
  F.bisect f a b epsilon Nothing Nothing


-- | Find a fixed point of the function @f@ with the search starting
--   at x0. We delegate to the version that returns the number of
--   iterations and simply discard the number of iterations.
--
fixed_point :: (Normed a,
                Algebra.Field.C b,
                Algebra.Absolute.C b,
                Ord b)
            => (a -> a) -- ^ The function @f@ to iterate.
            -> b       -- ^ The tolerance, @epsilon@.
            -> a       -- ^ The initial value @x0@.
            -> a       -- ^ The fixed point.
fixed_point f epsilon x0 =
  snd $ F.fixed_point_with_iterations f epsilon x0


-- | Return the number of iterations required to find a fixed point of
--   the function @f@ with the search starting at x0 and tolerance
--   @epsilon@. We delegate to the version that returns the number of
--   iterations and simply discard the fixed point.
fixed_point_iteration_count :: (Normed a,
                                Algebra.Field.C b,
                                Algebra.Absolute.C b,
                                Ord b)
                            => (a -> a) -- ^ The function @f@ to iterate.
                            -> b       -- ^ The tolerance, @epsilon@.
                            -> a       -- ^ The initial value @x0@.
                            -> Int       -- ^ The fixed point.
fixed_point_iteration_count f epsilon x0 =
  fst $ F.fixed_point_with_iterations f epsilon x0


-- | Returns a list of ratios,
--
--     ||x^{*} - x_{n+1}|| / ||x^{*} - x_{n}||^{p}
--
--   of fixed point iterations for the function @f@ with initial guess
--   @x0@ and @p@ some positive power.
--
--   This is used to determine the rate of convergence.
--
fixed_point_error_ratios :: (Normed a,
                             Algebra.Field.C b,
                             Algebra.Absolute.C b,
                             Ord b)
                   => (a -> a) -- ^ The function @f@ to iterate.
                   -> a       -- ^ The initial value @x0@.
                   -> a       -- ^ The true solution, @x_star@.
                   -> Integer -- ^ The power @p@.
                   -> [b]     -- ^ The resulting sequence of x_{n}.
fixed_point_error_ratios f x0 x_star p =
  zipWith (/) en_plus_one en_exp
  where
    xn = F.fixed_point_iterations f x0
    en = map (\x -> norm (x_star - x)) xn
    en_plus_one = tail en
    en_exp = map (^p) en



-- | The sequence x_{n} of values obtained by applying Newton's method
--   on the function @f@ and initial guess @x0@.
--
--   Examples:
--
--   Atkinson, p. 60.
--   >>> let f x = x^6 - x - 1
--   >>> let f' x = 6*x^5 - 1
--   >>> tail $ take 4 $ newton_iterations f f' 2
--   [1.6806282722513088,1.4307389882390624,1.2549709561094362]
--
newton_iterations :: (Algebra.Field.C a)
                    => (a -> a) -- ^ The function @f@ whose root we seek
                    -> (a -> a) -- ^ The derivative of @f@
                    -> a       -- ^ Initial guess, x-naught
                    -> [a]
newton_iterations f f' x0 =
  iterate next x0
  where
  next xn =
    xn - ( (f xn) / (f' xn) )


-- | Use Newton's method to find a root of @f@ near the initial guess
--   @x0@. If your guess is bad, this will recurse forever!
--
--   Examples:
--
--   Atkinson, p. 60.
--
--   >>> let f x = x^6 - x - 1
--   >>> let f' x = 6*x^5 - 1
--   >>> let Just root = newtons_method f f' (1/1000000) 2
--   >>> root
--   1.1347241385002211
--   >>> abs (f root) < 1/100000
--   True
--
--   >>> import Data.Number.BigFloat
--   >>> let eps = 1/(10^20) :: BigFloat Prec50
--   >>> let Just root = newtons_method f f' eps 2
--   >>> root
--   1.13472413840151949260544605450647284028100785303643e0
--   >>> abs (f root) < eps
--   True
--
newtons_method :: (Algebra.Field.C a, Algebra.Absolute.C a, Ord a)
                 => (a -> a) -- ^ The function @f@ whose root we seek
                 -> (a -> a) -- ^ The derivative of @f@
                 -> a       -- ^ The tolerance epsilon
                 -> a       -- ^ Initial guess, x-naught
                 -> Maybe a
newtons_method f f' epsilon x0 =
  find (\x -> abs (f x) < epsilon) x_n
  where
    x_n = newton_iterations f f' x0


-- | Takes a function @f@ of two arguments and repeatedly applies @f@
--   to the previous two values. Returns a list containing all
--   generated values, f(x0, x1), f(x1, x2), f(x2, x3)...
--
--   Examples:
--
--   >>> let fibs = iterate2 (+) 0 1
--   >>> take 15 fibs
--   [0,1,1,2,3,5,8,13,21,34,55,89,144,233,377]
--
iterate2 :: (a -> a -> a) -- ^ The function @f@
         -> a           -- ^ The initial value @x0@
         -> a           -- ^ The second value, @x1@
         -> [a]         -- ^ The result list, [x0, x1, ...]
iterate2 f x0 x1 =
  x0 : x1 : (go x0 x1)
  where
    go prev2 prev1 =
      let next = f prev2 prev1 in
        next : go prev1 next


-- | The sequence x_{n} of values obtained by applying the secant
--   method on the function @f@ and initial guesses @x0@, @x1@.
--
--   The recursion more or less implements a two-parameter 'iterate',
--   although one list is passed to the next iteration (as opposed to
--   one function argument, with iterate). At each step, we peel the
--   first two elements off the list and then compute/append elements
--   three, four... onto the end of the list.
--
--   Examples:
--
--   Atkinson, p. 67.
--   >>> let f x = x^6 - x - 1
--   >>> take 4 $ secant_iterations f 2 1
--   [2.0,1.0,1.0161290322580645,1.190577768676638]
--
secant_iterations :: (Algebra.Field.C a)
                    => (a -> a) -- ^ The function @f@ whose root we seek
                    -> a       -- ^ Initial guess, x-naught
                    -> a       -- ^ Second initial guess, x-one
                    -> [a]
secant_iterations f x0 x1 =
  iterate2 g x0 x1
  where
  g prev2 prev1 =
    let x_change = prev1 - prev2
        y_change = (f prev1) - (f prev2)
    in
      (prev1 - (f prev1 * (x_change / y_change)))


-- | Use the secant method to find a root of @f@ near the initial guesses
--   @x0@ and @x1@. If your guesses are bad, this will recurse forever!
--
--   Examples:
--
--   Atkinson, p. 67.
--   >>> let f x = x^6 - x - 1
--   >>> let Just root = secant_method f (1/10^9) 2 1
--   >>> root
--   1.1347241384015196
--   >>> abs (f root) < (1/10^9)
--   True
--
secant_method :: (Algebra.Field.C a, Algebra.Absolute.C a, Ord a)
                 => (a -> a) -- ^ The function @f@ whose root we seek
                 -> a       -- ^ The tolerance epsilon
                 -> a       -- ^ Initial guess, x-naught
                 -> a       -- ^ Second initial guess, x-one
                 -> Maybe a
secant_method f epsilon x0 x1
  = find (\x -> abs (f x) < epsilon) x_n
  where
    x_n = secant_iterations f x0 x1