+-- | Use Newton's method to find a root of @f@ near the initial guess
+-- @x0@. If your guess is bad, this will recurse forever!
newtons_method :: (Fractional a, Ord a)
=> (a -> a) -- ^ The function @f@ whose root we seek
-> (a -> a) -- ^ The derivative of @f@
= find (\x -> abs (f x) < epsilon) x_n
where
x_n = newton_iterations f f' x0
+
+
+
+-- | Takes a function @f@ of two arguments and repeatedly applies @f@
+-- to the previous two values. Returns a list containing all
+-- generated values, f(x0, x1), f(x1, x2), f(x2, x3)...
+--
+-- Examples:
+--
+-- >>> let fibs = iterate2 (+) 0 1
+-- >>> take 15 fibs
+-- [0,1,1,2,3,5,8,13,21,34,55,89,144,233,377]
+--
+iterate2 :: (a -> a -> a) -- ^ The function @f@
+ -> a -- ^ The initial value @x0@
+ -> a -- ^ The second value, @x1@
+ -> [a] -- ^ The result list, [x0, x1, ...]
+iterate2 f x0 x1 =
+ x0 : x1 : (go x0 x1)
+ where
+ go prev2 prev1 =
+ let next = f prev2 prev1 in
+ next : go prev1 next
+
+-- | The sequence x_{n} of values obtained by applying the secant
+-- method on the function @f@ and initial guesses @x0@, @x1@.
+--
+-- The recursion more or less implements a two-parameter 'iterate',
+-- although one list is passed to the next iteration (as opposed to
+-- one function argument, with iterate). At each step, we peel the
+-- first two elements off the list and then compute/append elements
+-- three, four... onto the end of the list.
+--
+-- Examples:
+--
+-- Atkinson, p. 67.
+-- >>> let f x = x^6 - x - 1
+-- >>> take 4 $ secant_iterations f 2 1
+-- [2.0,1.0,1.0161290322580645,1.190577768676638]
+--
+secant_iterations :: (Fractional a, Ord a)
+ => (a -> a) -- ^ The function @f@ whose root we seek
+ -> a -- ^ Initial guess, x-naught
+ -> a -- ^ Second initial guess, x-one
+ -> [a]
+secant_iterations f x0 x1 =
+ iterate2 g x0 x1
+ where
+ g prev2 prev1 =
+ let x_change = prev1 - prev2
+ y_change = (f prev1) - (f prev2)
+ in
+ (prev1 - (f prev1 * (x_change / y_change)))
+
+
+-- | Use the secant method to find a root of @f@ near the initial guesses
+-- @x0@ and @x1@. If your guesses are bad, this will recurse forever!
+--
+-- Examples:
+--
+-- Atkinson, p. 67.
+-- >>> let f x = x^6 - x - 1
+-- >>> let Just root = secant_method f (1/10^9) 2 1
+-- >>> root
+-- 1.1347241384015196
+-- >>> abs (f root) < (1/10^9)
+-- True
+--
+secant_method :: (Fractional a, Ord a)
+ => (a -> a) -- ^ The function @f@ whose root we seek
+ -> a -- ^ The tolerance epsilon
+ -> a -- ^ Initial guess, x-naught
+ -> a -- ^ Second initial guess, x-one
+ -> Maybe a
+secant_method f epsilon x0 x1
+ = find (\x -> abs (f x) < epsilon) x_n
+ where
+ x_n = secant_iterations f x0 x1