- The height of ``x`` is one (its first coordinate), and so the
- radius of the circle obtained from a height-one cross section is
- also one. Note that the last two coordinates of ``x`` are half
- of the way to the boundary of the cone, and in the direction of
- a 30-60-90 triangle. If one follows those coordinates, they hit
- at ``(1, sqrt(3)/2, 1/2)`` having unit norm. Thus the
- "horizontal" distance to the boundary of the cone is ``1 -
- norm(x)``, which simplifies to ``1/2``. And rather than involve
- a square root, we divide by two for a final safe radius of
- ``1/4``.
+ The height of ``x`` below is one (its first coordinate), and so
+ the radius of the circle obtained from a height-one cross
+ section is also one. Note that the last two coordinates of ``x``
+ are half of the way to the boundary of the cone, and in the
+ direction of a 30-60-90 triangle. If one follows those
+ coordinates, they hit at :math:`\left(1, \frac{\sqrt(3)}{2},
+ \frac{1}{2}\right)` having unit norm. Thus the "horizontal"
+ distance to the boundary of the cone is :math:`1 - \left\lVert x
+ \right\rVert`, which simplifies to :math:`1/2`. And rather than
+ involve a square root, we divide by two for a final safe radius
+ of :math:`1/4`.