from mjo.eja.eja_algebra import FiniteDimensionalEuclideanJordanAlgebra
from mjo.eja.eja_element import FiniteDimensionalEuclideanJordanAlgebraElement
-from mjo.eja.eja_utils import gram_schmidt
class FiniteDimensionalEuclideanJordanElementSubalgebraElement(FiniteDimensionalEuclideanJordanAlgebraElement):
"""
# because it's the maximal set of powers that could possibly
# be independent (by a dimension argument).
powers = [ elt**k for k in range(V.dimension()) ]
+ power_vectors = [ p.to_vector() for p in powers ]
+ P = matrix(field, power_vectors)
if orthonormalize_basis == False:
# In this case, we just need to figure out which elements
# of the "powers" list are redundant... First compute the
# vector subspace spanned by the powers of the given
# element.
- power_vectors = [ p.to_vector() for p in powers ]
# Figure out which powers form a linearly-independent set.
- ind_rows = matrix(field, power_vectors).pivot_rows()
+ ind_rows = P.pivot_rows()
# Pick those out of the list of all powers.
superalgebra_basis = tuple(map(powers.__getitem__, ind_rows))
else:
# If we're going to orthonormalize the basis anyway, we
# might as well just do Gram-Schmidt on the whole list of
- # powers. The redundant ones will get zero'd out.
- superalgebra_basis = gram_schmidt(powers)
- basis_vectors = [ b.to_vector() for b in superalgebra_basis ]
+ # powers. The redundant ones will get zero'd out. If this
+ # looks like a roundabout way to orthonormalize, it is.
+ # But converting everything from algebra elements to vectors
+ # to matrices and then back again turns out to be about
+ # as fast as reimplementing our own Gram-Schmidt that
+ # works in an EJA.
+ G,_ = P.gram_schmidt(orthonormal=True)
+ basis_vectors = [ g for g in G.rows() if not g.is_zero() ]
+ superalgebra_basis = [ self._superalgebra.from_vector(b)
+ for b in basis_vectors ]
W = V.span_of_basis( V.from_vector(v) for v in basis_vectors )
n = len(superalgebra_basis)