-- | The Roots.Fast module contains faster implementations of the -- 'Roots.Simple' algorithms. Generally, we will pass precomputed -- values to the next iteration of a function rather than passing -- the function and the points at which to (re)evaluate it. module Roots.Fast where has_root :: (Fractional a, Ord a, Ord b, Num b) => (a -> b) -- ^ The function @f@ -> a -- ^ The \"left\" endpoint, @a@ -> a -- ^ The \"right\" endpoint, @b@ -> Maybe a -- ^ The size of the smallest subinterval -- we'll examine, @epsilon@ -> Maybe b -- ^ Precoumpted f(a) -> Maybe b -- ^ Precoumpted f(b) -> Bool has_root f a b epsilon f_of_a f_of_b = if not ((signum (f_of_a')) * (signum (f_of_b')) == 1) then -- We don't care about epsilon here, there's definitely a root! True else if (b - a) <= epsilon' then -- Give up, return false. False else -- If either [a,c] or [c,b] have roots, we do too. (has_root f a c (Just epsilon') (Just f_of_a') Nothing) || (has_root f c b (Just epsilon') Nothing (Just f_of_b')) where -- If the size of the smallest subinterval is not specified, -- assume we just want to check once on all of [a,b]. epsilon' = case epsilon of Nothing -> (b-a) Just eps -> eps -- Compute f(a) and f(b) only if needed. f_of_a' = case f_of_a of Nothing -> f a Just v -> v f_of_b' = case f_of_b of Nothing -> f b Just v -> v c = (a + b)/2 bisect :: (Fractional a, Ord a, Num b, Ord b) => (a -> b) -- ^ The function @f@ whose root we seek -> a -- ^ The \"left\" endpoint of the interval, @a@ -> a -- ^ The \"right\" endpoint of the interval, @b@ -> a -- ^ The tolerance, @epsilon@ -> Maybe b -- ^ Precomputed f(a) -> Maybe b -- ^ Precomputed f(b) -> Maybe a bisect f a b epsilon f_of_a f_of_b -- We pass @epsilon@ to the 'has_root' function because if we want a -- result within epsilon of the true root, we need to know that -- there *is* a root within an interval of length epsilon. | not (has_root f a b (Just epsilon) (Just f_of_a') (Just f_of_b')) = Nothing | f_of_a' == 0 = Just a | f_of_b' == 0 = Just b | (b - c) < epsilon = Just c | otherwise = -- Use a 'prime' just for consistency. let f_of_c' = f c in if (has_root f a c (Just epsilon) (Just f_of_a') (Just f_of_c')) then bisect f a c epsilon (Just f_of_a') (Just f_of_c') else bisect f c b epsilon (Just f_of_c') (Just f_of_b') where -- Compute f(a) and f(b) only if needed. f_of_a' = case f_of_a of Nothing -> f a Just v -> v f_of_b' = case f_of_b of Nothing -> f b Just v -> v c = (a + b) / 2