From: Michael Orlitzky Date: Sun, 18 Nov 2012 07:23:54 +0000 (-0500) Subject: Fix legendre_p for finite field elements. X-Git-Url: http://gitweb.michael.orlitzky.com/?a=commitdiff_plain;h=c649291bc271a68a94e172f1946abffb6e5d9fdd;p=sage.d.git Fix legendre_p for finite field elements. --- diff --git a/mjo/orthogonal_polynomials.py b/mjo/orthogonal_polynomials.py index 808a558..0da947c 100644 --- a/mjo/orthogonal_polynomials.py +++ b/mjo/orthogonal_polynomials.py @@ -39,7 +39,7 @@ def legendre_p(n, x, a = -1, b = 1): Reuse the variable from a polynomial ring:: sage: P. = QQ[] - sage: legendre_p(2,t).simplify_rational() + sage: legendre_p(2,t) 3/2*t^2 - 1/2 If ``x`` is a real number, the result should be as well:: @@ -58,6 +58,11 @@ def legendre_p(n, x, a = -1, b = 1): [-179 242] [-484 547] + And finite field elements:: + + sage: legendre_P(3, GF(11)(5)) + 8 + TESTS: We should agree with Maxima for all `n`:: @@ -133,17 +138,30 @@ def legendre_p(n, x, a = -1, b = 1): # same field/ring as `x`. return x.parent()(1) - # Even though we know a,b are real we use the symbolic ring. This - # lets us return pretty expressions where possible. - a = SR(a) - b = SR(b) - n = ZZ(n) # Ensure that 1/(2**n) is not integer division. - dn = 1/(2**n) + # Even though we know a,b are real we use a different ring. We + # prefer ZZ so that we can support division of finite field + # elements by (a-b). Eventually this should be supported for QQ as + # well, although it does not work at the moment. The preference of + # SR over RR is to return something attractive when e.g. a=pi. + if a in ZZ: + a = ZZ(a) + else: + a = SR(a) + + if b in ZZ: + b = ZZ(b) + else: + b = SR(b) + + # Ensure that (2**n) is an element of ZZ. This is used later -- + # we can divide finite field elements by integers but we can't + # multiply them by rationals at the moment. + n = ZZ(n) def phi(t): - # This is an affine map from [a,b] into [-1,1] and so preserves - # orthogonality. - return (2 / (b-a))*t + 1 - (2*b)/(b-a) + # This is an affine map from [a,b] into [-1,1] and so + # preserves orthogonality. + return (a + b - 2*t)/(a - b) def c(m): return binomial(n,m)*binomial(n, n-m) @@ -153,6 +171,7 @@ def legendre_p(n, x, a = -1, b = 1): return ( ((phi(x) - 1)**(n-m)) * (phi(x) + 1)**m ) # From Abramowitz & Stegun, (22.3.2) with alpha = beta = 0. - P = dn * sum([ c(m)*g(m) for m in range(0,n+1) ]) + # Also massaged to support finite field elements. + P = sum([ c(m)*g(m) for m in range(0,n+1) ])/(2**n) return P