X-Git-Url: http://gitweb.michael.orlitzky.com/?a=blobdiff_plain;f=src%2FTests%2FCube.hs;h=888c48f4840d54ec62f95f0f3e4aa0fe17519e7c;hb=a32bce2dc24c2371099f0927ac5959c893d025a8;hp=26d4d33f5ab7e21f3b85fc032ae98113edd6b25d;hpb=2064e9a7da32813c6dce843127e2306b841df353;p=spline3.git diff --git a/src/Tests/Cube.hs b/src/Tests/Cube.hs index 26d4d33..888c48f 100644 --- a/src/Tests/Cube.hs +++ b/src/Tests/Cube.hs @@ -1,7 +1,6 @@ module Tests.Cube where -import Debug.Trace (trace) import Test.QuickCheck import Comparisons @@ -263,16 +262,223 @@ prop_tetrahedron23_volumes_positive c = volume (tetrahedron23 c) > 0 +-- | Given in Sorokina and Zeilfelder, p. 79. Note that the third and +-- fourth indices of c-t3 have been switched. This is because we +-- store the triangles oriented such that their volume is +-- positive. If T and T-tilde share and v3,v3-tilde point +-- in opposite directions, one of them has to have negative volume! +prop_c0120_identity1 :: Cube -> Bool +prop_c0120_identity1 cube = + c t0 0 1 2 0 ~= (c t0 0 0 2 1 + c t3 0 0 1 2) / 2 + where + t0 = tetrahedron0 cube + t3 = tetrahedron3 cube + + +-- | Given in Sorokina and Zeilfelder, p. 79. Note that the third and +-- fourth indices of c-t3 have been switched. This is because we +-- store the triangles oriented such that their volume is +-- positive. If T and T-tilde share and v3,v3-tilde point +-- in opposite directions, one of them has to have negative volume! +prop_c0210_identity1 :: Cube -> Bool +prop_c0210_identity1 cube = + c t0 0 2 1 0 ~= (c t0 0 1 1 1 + c t3 0 1 1 1) / 2 + where + t0 = tetrahedron0 cube + t3 = tetrahedron3 cube + + +-- | Given in Sorokina and Zeilfelder, p. 79. Note that the third and +-- fourth indices of c-t3 have been switched. This is because we +-- store the triangles oriented such that their volume is +-- positive. If T and T-tilde share and v3,v3-tilde point +-- in opposite directions, one of them has to have negative volume! +prop_c0300_identity1 :: Cube -> Bool +prop_c0300_identity1 cube = + c t0 0 3 0 0 ~= (c t0 0 2 0 1 + c t3 0 2 1 0) / 2 + where + t0 = tetrahedron0 cube + t3 = tetrahedron3 cube + + +-- | Given in Sorokina and Zeilfelder, p. 79. Note that the third and +-- fourth indices of c-t3 have been switched. This is because we +-- store the triangles oriented such that their volume is +-- positive. If T and T-tilde share and v3,v3-tilde point +-- in opposite directions, one of them has to have negative volume! +prop_c1110_identity :: Cube -> Bool +prop_c1110_identity cube = + c t0 1 1 1 0 ~= (c t0 1 0 1 1 + c t3 1 0 1 1) / 2 + where + t0 = tetrahedron0 cube + t3 = tetrahedron3 cube + + +-- | Given in Sorokina and Zeilfelder, p. 79. Note that the third and +-- fourth indices of c-t3 have been switched. This is because we +-- store the triangles oriented such that their volume is +-- positive. If T and T-tilde share and v3,v3-tilde point +-- in opposite directions, one of them has to have negative volume! +prop_c1200_identity1 :: Cube -> Bool +prop_c1200_identity1 cube = + c t0 1 2 0 0 ~= (c t0 1 1 0 1 + c t3 1 1 1 0) / 2 + where + t0 = tetrahedron0 cube + t3 = tetrahedron3 cube + + +-- | Given in Sorokina and Zeilfelder, p. 79. Note that the third and +-- fourth indices of c-t3 have been switched. This is because we +-- store the triangles oriented such that their volume is +-- positive. If T and T-tilde share and v3,v3-tilde point +-- in opposite directions, one of them has to have negative volume! +prop_c2100_identity1 :: Cube -> Bool +prop_c2100_identity1 cube = + c t0 2 1 0 0 ~= (c t0 2 0 0 1 + c t3 2 0 1 0) / 2 + where + t0 = tetrahedron0 cube + t3 = tetrahedron3 cube + + + +-- | Given in Sorokina and Zeilfelder, p. 79. Note that the third and +-- fourth indices of c-t1 have been switched. This is because we +-- store the triangles oriented such that their volume is +-- positive. If T and T-tilde share and v2,v2-tilde point +-- in opposite directions, one of them has to have negative volume! +prop_c0102_identity1 :: Cube -> Bool +prop_c0102_identity1 cube = + c t0 0 1 0 2 ~= (c t0 0 0 1 2 + c t1 0 0 2 1) / 2 + where + t0 = tetrahedron0 cube + t1 = tetrahedron1 cube + + +-- | Given in Sorokina and Zeilfelder, p. 79. Note that the third and +-- fourth indices of c-t1 have been switched. This is because we +-- store the triangles oriented such that their volume is +-- positive. If T and T-tilde share and v2,v2-tilde point +-- in opposite directions, one of them has to have negative volume! +prop_c0201_identity1 :: Cube -> Bool +prop_c0201_identity1 cube = + c t0 0 2 0 1 ~= (c t0 0 1 1 1 + c t1 0 1 1 1) / 2 + where + t0 = tetrahedron0 cube + t1 = tetrahedron1 cube + + +-- | Given in Sorokina and Zeilfelder, p. 79. Note that the third and +-- fourth indices of c-t1 have been switched. This is because we +-- store the triangles oriented such that their volume is +-- positive. If T and T-tilde share and v2,v2-tilde point +-- in opposite directions, one of them has to have negative volume! +prop_c0300_identity2 :: Cube -> Bool +prop_c0300_identity2 cube = + c t0 0 3 0 0 ~= (c t0 0 2 1 0 + c t1 0 2 0 1) / 2 + where + t0 = tetrahedron0 cube + t1 = tetrahedron1 cube + + +-- | Given in Sorokina and Zeilfelder, p. 79. Note that the third and +-- fourth indices of c-t1 have been switched. This is because we +-- store the triangles oriented such that their volume is +-- positive. If T and T-tilde share and v2,v2-tilde point +-- in opposite directions, one of them has to have negative volume! +prop_c1101_identity :: Cube -> Bool +prop_c1101_identity cube = + c t0 1 1 0 1 ~= (c t0 1 0 1 1 + c t1 1 0 1 1) / 2 + where + t0 = tetrahedron0 cube + t1 = tetrahedron1 cube + + +-- | Given in Sorokina and Zeilfelder, p. 79. Note that the third and +-- fourth indices of c-t1 have been switched. This is because we +-- store the triangles oriented such that their volume is +-- positive. If T and T-tilde share and v2,v2-tilde point +-- in opposite directions, one of them has to have negative volume! +prop_c1200_identity2 :: Cube -> Bool +prop_c1200_identity2 cube = + c t0 1 2 0 0 ~= (c t0 1 1 1 0 + c t1 1 1 0 1) / 2 + where + t0 = tetrahedron0 cube + t1 = tetrahedron1 cube + + +-- | Given in Sorokina and Zeilfelder, p. 79. Note that the third and +-- fourth indices of c-t1 have been switched. This is because we +-- store the triangles oriented such that their volume is +-- positive. If T and T-tilde share and v2,v2-tilde point +-- in opposite directions, one of them has to have negative volume! +prop_c2100_identity2 :: Cube -> Bool +prop_c2100_identity2 cube = + c t0 2 1 0 0 ~= (c t0 2 0 1 0 + c t1 2 0 0 1) / 2 + where + t0 = tetrahedron0 cube + t1 = tetrahedron1 cube + + +prop_t0_shares_edge_with_t6 :: Cube -> Bool +prop_t0_shares_edge_with_t6 cube = + (v2 t0) == (v3 t6) && (v3 t0) == (v2 t6) + where + t0 = tetrahedron0 cube + t6 = tetrahedron6 cube + + +-- | Given in Sorokina and Zeilfelder, p. 79. +prop_c3000_identity :: Cube -> Bool +prop_c3000_identity cube = + c t0 3 0 0 0 ~= c t0 2 1 0 0 + c t6 2 1 0 0 - ((c t0 2 0 1 0 + c t0 2 0 0 1)/ 2) + where + t0 = tetrahedron0 cube + t6 = tetrahedron6 cube + + -- | Given in Sorokina and Zeilfelder, p. 79. ---prop_c0120_identity1 :: Cube -> Bool ---prop_c0120_identity1 cube = --- c0 ~= (c1 + c2) / 2 --- where --- c0 = trace ("c0 :" ++ (show (c t0 0 1 2 0))) (c t0 0 1 2 0) --- c1 = trace ("c1 :" ++ (show (c t0 0 0 2 1))) (c t0 0 0 2 1) --- c2 = trace ("c2 :" ++ (show (c t1 0 0 2 1))) (c t1 0 0 2 1) --- t0 = tetrahedron0 cube --- t1 = tetrahedron1 cube +prop_c2010_identity :: Cube -> Bool +prop_c2010_identity cube = + c t0 2 0 1 0 ~= c t0 1 1 1 0 + c t6 1 1 1 0 - ((c t0 1 0 2 0 + c t0 1 0 1 1)/ 2) + where + t0 = tetrahedron0 cube + t6 = tetrahedron6 cube + + +-- | Given in Sorokina and Zeilfelder, p. 79. +prop_c2001_identity :: Cube -> Bool +prop_c2001_identity cube = + c t0 2 0 0 1 ~= c t0 1 1 0 1 + c t6 1 1 0 1 - ((c t0 1 0 0 2 + c t0 1 0 1 1)/ 2) + where + t0 = tetrahedron0 cube + t6 = tetrahedron6 cube + +-- | Given in Sorokina and Zeilfelder, p. 79. +prop_c1020_identity :: Cube -> Bool +prop_c1020_identity cube = + c t0 1 0 2 0 ~= c t0 0 1 2 0 + c t6 0 1 2 0 - ((c t0 0 0 3 0 + c t0 0 0 2 1)/ 2) + where + t0 = tetrahedron0 cube + t6 = tetrahedron6 cube + + +-- | Given in Sorokina and Zeilfelder, p. 79. +prop_c1002_identity :: Cube -> Bool +prop_c1002_identity cube = + c t0 1 0 0 2 ~= c t0 0 1 0 2 + c t6 0 1 0 2 - ((c t0 0 0 0 3 + c t0 0 0 1 2)/ 2) + where + t0 = tetrahedron0 cube + t6 = tetrahedron6 cube + + +-- | Given in Sorokina and Zeilfelder, p. 79. +prop_c1011_identity :: Cube -> Bool +prop_c1011_identity cube = + c t0 1 0 1 1 ~= c t0 0 1 1 1 + c t6 0 1 1 1 - ((c t0 0 0 1 2 + c t0 0 0 2 1)/ 2) + where + t0 = tetrahedron0 cube + t6 = tetrahedron6 cube + -- | Given in Sorokina and Zeilfelder, p. 78.