X-Git-Url: http://gitweb.michael.orlitzky.com/?a=blobdiff_plain;f=src%2FTests%2FCube.hs;h=666fde8899c168f85b061430ce06f5ee3ca93e1f;hb=5109e41113a39024ef3fe799abb08de4a2ac74b0;hp=5485046ec46b934cc423bb9dedb0054eab9d289b;hpb=01925d099b231a128f6bd51abd61bf9ff9c424b6;p=spline3.git diff --git a/src/Tests/Cube.hs b/src/Tests/Cube.hs index 5485046..666fde8 100644 --- a/src/Tests/Cube.hs +++ b/src/Tests/Cube.hs @@ -7,7 +7,9 @@ import Comparisons import Cube import FunctionValues (FunctionValues) import Tests.FunctionValues () -import Tetrahedron (v0, volume) +import Tetrahedron (b0, b1, b2, b3, c, + Tetrahedron(Tetrahedron), + v0, v1, v2, v3, volume) instance Arbitrary Cube where arbitrary = do @@ -258,3 +260,98 @@ prop_tetrahedron22_volumes_positive c = prop_tetrahedron23_volumes_positive :: Cube -> Bool prop_tetrahedron23_volumes_positive c = volume (tetrahedron23 c) > 0 + + +-- | Given in Sorokina and Zeilfelder, p. 79. Note that the third and +-- fourth indices of c-t3 have been switched. This is because we +-- store the triangles oriented such that their volume is +-- positive. If T and T-tilde share and v3,v3-tilde point +-- in opposite directions, one of them has to have negative volume! +prop_c0120_identity1 :: Cube -> Bool +prop_c0120_identity1 cube = + c t0 0 1 2 0 ~= (c t0 0 0 2 1 + c t3 0 0 1 2) / 2 + where + t0 = tetrahedron0 cube + t3 = tetrahedron3 cube + + +-- | Given in Sorokina and Zeilfelder, p. 79. Note that the third and +-- fourth indices of c-t3 have been switched. This is because we +-- store the triangles oriented such that their volume is +-- positive. If T and T-tilde share and v3,v3-tilde point +-- in opposite directions, one of them has to have negative volume! +prop_c0210_identity1 :: Cube -> Bool +prop_c0210_identity1 cube = + c t0 0 2 1 0 ~= (c t0 0 1 1 1 + c t3 0 1 1 1) / 2 + where + t0 = tetrahedron0 cube + t3 = tetrahedron3 cube + + +-- | Given in Sorokina and Zeilfelder, p. 79. Note that the third and +-- fourth indices of c-t3 have been switched. This is because we +-- store the triangles oriented such that their volume is +-- positive. If T and T-tilde share and v3,v3-tilde point +-- in opposite directions, one of them has to have negative volume! +prop_c0300_identity1 :: Cube -> Bool +prop_c0300_identity1 cube = + c t0 0 3 0 0 ~= (c t0 0 2 0 1 + c t3 0 2 1 0) / 2 + where + t0 = tetrahedron0 cube + t3 = tetrahedron3 cube + + +-- | Given in Sorokina and Zeilfelder, p. 79. Note that the third and +-- fourth indices of c-t3 have been switched. This is because we +-- store the triangles oriented such that their volume is +-- positive. If T and T-tilde share and v3,v3-tilde point +-- in opposite directions, one of them has to have negative volume! +prop_c1110_identity :: Cube -> Bool +prop_c1110_identity cube = + c t0 1 1 1 0 ~= (c t0 1 0 1 1 + c t3 1 0 1 1) / 2 + where + t0 = tetrahedron0 cube + t3 = tetrahedron3 cube + + +-- | Given in Sorokina and Zeilfelder, p. 79. Note that the third and +-- fourth indices of c-t3 have been switched. This is because we +-- store the triangles oriented such that their volume is +-- positive. If T and T-tilde share and v3,v3-tilde point +-- in opposite directions, one of them has to have negative volume! +prop_c1200_identity1 :: Cube -> Bool +prop_c1200_identity1 cube = + c t0 1 2 0 0 ~= (c t0 1 1 0 1 + c t3 1 1 1 0) / 2 + where + t0 = tetrahedron0 cube + t3 = tetrahedron3 cube + + +-- | Given in Sorokina and Zeilfelder, p. 79. Note that the third and +-- fourth indices of c-t3 have been switched. This is because we +-- store the triangles oriented such that their volume is +-- positive. If T and T-tilde share and v3,v3-tilde point +-- in opposite directions, one of them has to have negative volume! +prop_c2100_identity1 :: Cube -> Bool +prop_c2100_identity1 cube = + c t0 2 1 0 0 ~= (c t0 2 0 0 1 + c t3 2 0 1 0) / 2 + where + t0 = tetrahedron0 cube + t3 = tetrahedron3 cube + + + +-- | Given in Sorokina and Zeilfelder, p. 78. +-- prop_cijk1_identity :: Cube -> Bool +-- prop_cijk1_identity cube = +-- and [ c t0 i j k 1 ~= +-- (c t1 (i+1) j k 0) * ((b0 t0) (v3 t1)) + +-- (c t1 i (j+1) k 0) * ((b1 t0) (v3 t1)) + +-- (c t1 i j (k+1) 0) * ((b2 t0) (v3 t1)) + +-- (c t1 i j k 1) * ((b3 t0) (v3 t1)) | i <- [0..2], +-- j <- [0..2], +-- k <- [0..2], +-- i + j + k == 2] +-- where +-- t0 = tetrahedron0 cube +-- t1 = tetrahedron1 cube