X-Git-Url: http://gitweb.michael.orlitzky.com/?a=blobdiff_plain;f=dunshire%2Fgames.py;h=51c97add2314a9de54f8bb7d76f56ac13d6a1dd9;hb=5a78134ba154ef2e4855b791d1bdb45f26bfdf57;hp=130176b63bf9a276541609ad70b25f2c0b7a7d79;hpb=13b585b28aaacb1d603c3ae41614bacf613afa14;p=dunshire.git diff --git a/dunshire/games.py b/dunshire/games.py index 130176b..51c97ad 100644 --- a/dunshire/games.py +++ b/dunshire/games.py @@ -887,49 +887,46 @@ class SymmetricLinearGame: >>> SLG.solution().game_value() < -ABS_TOL True - Tests - ----- - The following two games are problematic numerically, but we should be able to solve them:: - >>> from dunshire import * - >>> L = [[-0.95237953890954685221, 1.83474556206462535712], - ... [ 1.30481749924621448500, 1.65278664543326403447]] - >>> K = NonnegativeOrthant(2) - >>> e1 = [0.95477167524644313001, 0.63270781756540095397] - >>> e2 = [0.39633793037154141370, 0.10239281495640320530] - >>> SLG = SymmetricLinearGame(L, K, e1, e2) - >>> print(SLG.solution()) - Game value: 18.767... - Player 1 optimal: - [-0.000...] - [ 9.766...] - Player 2 optimal: - [1.047...] - [0.000...] + >>> from dunshire import * + >>> L = [[-0.95237953890954685221, 1.83474556206462535712], + ... [ 1.30481749924621448500, 1.65278664543326403447]] + >>> K = NonnegativeOrthant(2) + >>> e1 = [0.95477167524644313001, 0.63270781756540095397] + >>> e2 = [0.39633793037154141370, 0.10239281495640320530] + >>> SLG = SymmetricLinearGame(L, K, e1, e2) + >>> print(SLG.solution()) + Game value: 18.767... + Player 1 optimal: + [-0.000...] + [ 9.766...] + Player 2 optimal: + [1.047...] + [0.000...] :: - >>> from dunshire import * - >>> L = [[1.54159395026049472754, 2.21344728574316684799], - ... [1.33147433507846657541, 1.17913616272988108769]] - >>> K = NonnegativeOrthant(2) - >>> e1 = [0.39903040089404784307, 0.12377403622479113410] - >>> e2 = [0.15695181142215544612, 0.85527381344651265405] - >>> SLG = SymmetricLinearGame(L, K, e1, e2) - >>> print(SLG.solution()) - Game value: 24.614... - Player 1 optimal: - [ 6.371...] - [-0.000...] - Player 2 optimal: - [2.506...] - [0.000...] + >>> from dunshire import * + >>> L = [[1.54159395026049472754, 2.21344728574316684799], + ... [1.33147433507846657541, 1.17913616272988108769]] + >>> K = NonnegativeOrthant(2) + >>> e1 = [0.39903040089404784307, 0.12377403622479113410] + >>> e2 = [0.15695181142215544612, 0.85527381344651265405] + >>> SLG = SymmetricLinearGame(L, K, e1, e2) + >>> print(SLG.solution()) + Game value: 24.614... + Player 1 optimal: + [ 6.371...] + [-0.000...] + Player 2 optimal: + [2.506...] + [0.000...] """ try: - opts = {'show_progress': options.VERBOSE} + opts = {'show_progress': False} soln_dict = solvers.conelp(self._c(), self._G(), self._h(), @@ -942,6 +939,7 @@ class SymmetricLinearGame: # Oops, CVXOPT tried to take the square root of a # negative number. Report some details about the game # rather than just the underlying CVXOPT crash. + printing.options['dformat'] = options.DEBUG_FLOAT_FORMAT raise PoorScalingException(self) else: raise error @@ -966,6 +964,7 @@ class SymmetricLinearGame: # that CVXOPT is convinced the problem is infeasible (and that # cannot happen). if soln_dict['status'] in ['primal infeasible', 'dual infeasible']: + printing.options['dformat'] = options.DEBUG_FLOAT_FORMAT raise GameUnsolvableException(self, soln_dict) # The "optimal" and "unknown" results, we actually treat the @@ -979,11 +978,13 @@ class SymmetricLinearGame: # it) because otherwise CVXOPT might return "unknown" and give # us two points in the cone that are nowhere near optimal. if abs(p1_value - p2_value) > 2*options.ABS_TOL: + printing.options['dformat'] = options.DEBUG_FLOAT_FORMAT raise GameUnsolvableException(self, soln_dict) # And we also check that the points it gave us belong to the # cone, just in case... if (p1_optimal not in self._K) or (p2_optimal not in self._K): + printing.options['dformat'] = options.DEBUG_FLOAT_FORMAT raise GameUnsolvableException(self, soln_dict) # For the game value, we could use any of: @@ -997,7 +998,7 @@ class SymmetricLinearGame: # makes the most sense to just use that, even if it means we # can't test the fact that p1_value/p2_value are close to the # payoff. - payoff = self.payoff(p1_optimal,p2_optimal) + payoff = self.payoff(p1_optimal, p2_optimal) return Solution(payoff, p1_optimal, p2_optimal)