from sage.all import *
-
-def random_cone(min_dim=None, max_dim=None, min_rays=None, max_rays=None):
+# TODO: This test fails, maybe due to a bug in the existing cone code.
+# If we request enough generators to span the space, then the returned
+# cone should equal the ambient space::
+#
+# sage: K = random_cone(min_dim=5, max_dim=5, min_rays=10, max_rays=10)
+# sage: K.lines().dimension() == K.lattice_dim()
+# True
+
+def random_cone(min_dim=0, max_dim=None, min_rays=0, max_rays=None):
r"""
Generate a random rational convex polyhedral cone.
Lower and upper bounds may be provided for both the dimension of the
- ambient space and the number of generating rays of the cone. Any
- parameters left unspecified will be chosen randomly.
+ ambient space and the number of generating rays of the cone. If a
+ lower bound is left unspecified, it defaults to zero. Unspecified
+ upper bounds will be chosen randomly.
+
+ The number of generating rays is naturally limited to twice the
+ dimension of the ambient space. Take for example $\mathbb{R}^{2}$.
+ You could have the generators $\left\{ \pm e_{1}, \pm e_{2}
+ \right\}$, with cardinality $4 = 2 \cdot 2$; however any other ray
+ in the space is a nonnegative linear combination of those four.
+
+ .. NOTE:
+
+ If you do not explicitly request more than ``2 * max_dim`` rays,
+ a larger number may still be randomly generated. In that case,
+ the returned cone will simply be equal to the entire space.
INPUT:
- - ``min_dim`` (default: random) -- The minimum dimension of the ambient
- lattice.
+ - ``min_dim`` (default: zero) -- A nonnegative integer representing the
+ minimum dimension of the ambient lattice.
- - ``max_dim`` (default: random) -- The maximum dimension of the ambient
+ - ``max_dim`` (default: random) -- A nonnegative integer representing
+ the maximum dimension of the ambient
lattice.
- - ``min_rays`` (default: random) -- The minimum number of generating rays
- of the cone.
+ - ``min_rays`` (default: zero) -- A nonnegative integer representing the
+ minimum number of generating rays of the
+ cone.
- - ``max_rays`` (default: random) -- The maximum number of generating rays
- of the cone.
+ - ``max_rays`` (default: random) -- A nonnegative integer representing the
+ maximum number of generating rays of
+ the cone.
OUTPUT:
A new, randomly generated cone.
+ A ``ValueError` will be thrown under the following conditions:
+
+ * Any of ``min_dim``, ``max_dim``, ``min_rays``, or ``max_rays``
+ are negative.
+
+ * ``max_dim`` is less than ``min_dim``.
+
+ * ``max_rays`` is less than ``min_rays``.
+
+ * ``min_rays`` is greater than twice ``max_dim``.
+
+ EXAMPLES:
+
+ If we set the lower/upper bounds to zero, then our result is
+ predictable::
+
+ sage: random_cone(0,0,0,0)
+ 0-d cone in 0-d lattice N
+
+ We can predict the dimension when ``min_dim == max_dim``::
+
+ sage: random_cone(min_dim=4, max_dim=4, min_rays=0, max_rays=0)
+ 0-d cone in 4-d lattice N
+
+ Likewise for the number of rays when ``min_rays == max_rays``::
+
+ sage: random_cone(min_dim=10, max_dim=10, min_rays=10, max_rays=10)
+ 10-d cone in 10-d lattice N
+
TESTS:
It's hard to test the output of a random process, but we can at
least make sure that we get a cone back::
- sage: from sage.geometry.cone import is_Cone
- sage: K = random_cone()
- sage: is_Cone(K) # long time
+ sage: from sage.geometry.cone import is_Cone # long time
+ sage: K = random_cone() # long time
+ sage: is_Cone(K) # long time
True
+ The upper/lower bounds are respected::
+
+ sage: K = random_cone(min_dim=5, max_dim=10, min_rays=3, max_rays=4)
+ sage: 5 <= K.lattice_dim() and K.lattice_dim() <= 10
+ True
+ sage: 3 <= K.nrays() and K.nrays() <= 4
+ True
+
+ Ensure that an exception is raised when either lower bound is greater
+ than its respective upper bound::
+
+ sage: random_cone(min_dim=5, max_dim=2)
+ Traceback (most recent call last):
+ ...
+ ValueError: max_dim cannot be less than min_dim.
+
+ sage: random_cone(min_rays=5, max_rays=2)
+ Traceback (most recent call last):
+ ...
+ ValueError: max_rays cannot be less than min_rays.
+
+ And if we request too many rays::
+
+ sage: random_cone(min_rays=5, max_dim=1)
+ Traceback (most recent call last):
+ ...
+ ValueError: min_rays cannot be larger than twice max_dim.
+
"""
+ # Catch obvious mistakes so that we can generate clear error
+ # messages.
+
+ if min_dim < 0:
+ raise ValueError('min_dim must be nonnegative.')
+
+ if min_rays < 0:
+ raise ValueError('min_rays must be nonnegative.')
+
+ if max_dim is not None:
+ if max_dim < 0:
+ raise ValueError('max_dim must be nonnegative.')
+ if (max_dim < min_dim):
+ raise ValueError('max_dim cannot be less than min_dim.')
+ if min_rays > 2*max_dim:
+ raise ValueError('min_rays cannot be larger than twice max_dim.')
+
+ if max_rays is not None:
+ if max_rays < 0:
+ raise ValueError('max_rays must be nonnegative.')
+ if (max_rays < min_rays):
+ raise ValueError('max_rays cannot be less than min_rays.')
+
+
def random_min_max(l,u):
r"""
- We need to handle four cases to prevent us from doing
- something stupid like having an upper bound that's lower than
- our lower bound. And we would need to repeat all of that logic
- for the dimension/rays, so we consolidate it here.
+ We need to handle two cases for the upper bounds, and we need to do
+ the same thing for max_dim/max_rays. So we consolidate the logic here.
"""
- if l is None and u is None:
- # They're both random, just return a random nonnegative
- # integer.
- return ZZ.random_element().abs()
-
- if l is not None and u is not None:
- # Both were specified. Again, just make up a number and
- # return it. If the user wants to give us u < l then he
- # can have an exception.
- return ZZ.random_element(l,u)
-
- if l is not None and u is None:
- # In this case, we're generating the upper bound randomly
- # GIVEN A LOWER BOUND. So we add a random nonnegative
- # integer to the given lower bound.
- u = l + ZZ.random_element().abs()
- return ZZ.random_element(l,u)
-
- # Here we must be in the only remaining case, where we are
- # given an upper bound but no lower bound. We might as well
- # use zero.
- return ZZ.random_element(0,u)
+ if u is None:
+ # The upper bound is unspecified; return a random integer
+ # in [l,infinity).
+ return l + ZZ.random_element().abs()
+ else:
+ # We have an upper bound, and it's greater than or equal
+ # to our lower bound. So we generate a random integer in
+ # [0,u-l], and then add it to l to get something in
+ # [l,u]. To understand the "+1", check the
+ # ZZ.random_element() docs.
+ return l + ZZ.random_element(u - l + 1)
+
d = random_min_max(min_dim, max_dim)
r = random_min_max(min_rays, max_rays)
L = ToricLattice(d)
- rays = [L.random_element() for i in range(0,r)]
- # We pass the lattice in case there are no rays.
- return Cone(rays, lattice=L)
+ # The rays are trickier to generate, since we could generate v and
+ # 2*v as our "two rays." In that case, the resuting cone would
+ # have one generating ray. To avoid such a situation, we start by
+ # generating ``r`` rays where ``r`` is the number we want to end
+ # up with.
+ #
+ # However, since we're going to *check* whether or not we actually
+ # have ``r``, we need ``r`` rays to be attainable. So we need to
+ # limit ``r`` to twice the dimension of the ambient space.
+ #
+ r = min(r, 2*d)
+ rays = [L.random_element() for i in range(0, r)]
+
+ # (The lattice parameter is required when no rays are given, so we
+ # pass it just in case ``r == 0``).
+ K = Cone(rays, lattice=L)
+
+ # Now if we generated two of the "same" rays, we'll have fewer
+ # generating rays than ``r``. In that case, we keep making up new
+ # rays and recreating the cone until we get the right number of
+ # independent generators.
+ while r > K.nrays():
+ rays.append(L.random_element())
+ K = Cone(rays)
+
+ return K
+
+
+def discrete_complementarity_set(K):
+ r"""
+ Compute the discrete complementarity set of this cone.
+
+ The complementarity set of this cone is the set of all orthogonal
+ pairs `(x,s)` such that `x` is in this cone, and `s` is in its
+ dual. The discrete complementarity set restricts `x` and `s` to be
+ generators of their respective cones.
+
+ OUTPUT:
+
+ A list of pairs `(x,s)` such that,
+
+ * `x` is in this cone.
+ * `x` is a generator of this cone.
+ * `s` is in this cone's dual.
+ * `s` is a generator of this cone's dual.
+ * `x` and `s` are orthogonal.
+
+ EXAMPLES:
+
+ The discrete complementarity set of the nonnegative orthant consists
+ of pairs of standard basis vectors::
+
+ sage: K = Cone([(1,0),(0,1)])
+ sage: discrete_complementarity_set(K)
+ [((1, 0), (0, 1)), ((0, 1), (1, 0))]
+
+ If the cone consists of a single ray, the second components of the
+ discrete complementarity set should generate the orthogonal
+ complement of that ray::
+
+ sage: K = Cone([(1,0)])
+ sage: discrete_complementarity_set(K)
+ [((1, 0), (0, 1)), ((1, 0), (0, -1))]
+ sage: K = Cone([(1,0,0)])
+ sage: discrete_complementarity_set(K)
+ [((1, 0, 0), (0, 1, 0)),
+ ((1, 0, 0), (0, -1, 0)),
+ ((1, 0, 0), (0, 0, 1)),
+ ((1, 0, 0), (0, 0, -1))]
+
+ When the cone is the entire space, its dual is the trivial cone, so
+ the discrete complementarity set is empty::
+
+ sage: K = Cone([(1,0),(-1,0),(0,1),(0,-1)])
+ sage: discrete_complementarity_set(K)
+ []
+
+ TESTS:
+
+ The complementarity set of the dual can be obtained by switching the
+ components of the complementarity set of the original cone::
+
+ sage: K1 = random_cone(max_dim=10, max_rays=10)
+ sage: K2 = K1.dual()
+ sage: expected = [(x,s) for (s,x) in discrete_complementarity_set(K2)]
+ sage: actual = discrete_complementarity_set(K1)
+ sage: actual == expected
+ True
+
+ """
+ V = K.lattice().vector_space()
+
+ # Convert the rays to vectors so that we can compute inner
+ # products.
+ xs = [V(x) for x in K.rays()]
+ ss = [V(s) for s in K.dual().rays()]
+
+ return [(x,s) for x in xs for s in ss if x.inner_product(s) == 0]
def lyapunov_rank(K):
The Lyapunov rank should be additive on a product of cones::
- sage: K1 = random_cone(0,10,0,10)
- sage: K2 = random_cone(0,10,0,10)
+ sage: K1 = random_cone(max_dim=10, max_rays=10)
+ sage: K2 = random_cone(max_dim=10, max_rays=10)
sage: K = K1.cartesian_product(K2)
sage: lyapunov_rank(K) == lyapunov_rank(K1) + lyapunov_rank(K2)
True
The dual cone `K^{*}` of ``K`` should have the same Lyapunov rank as ``K``
itself::
- sage: K = random_cone(0,10,0,10)
+ sage: K = random_cone(max_dim=10, max_rays=10)
sage: lyapunov_rank(K) == lyapunov_rank(K.dual())
True
"""
V = K.lattice().vector_space()
- xs = [V(x) for x in K.rays()]
- ss = [V(s) for s in K.dual().rays()]
-
- # WARNING: This isn't really C(K), it only contains the pairs
- # (x,s) in C(K) where x,s are extreme in their respective cones.
- C_of_K = [(x,s) for x in xs for s in ss if x.inner_product(s) == 0]
+ C_of_K = discrete_complementarity_set(K)
- matrices = [x.column() * s.row() for (x,s) in C_of_K]
+ matrices = [x.tensor_product(s) for (x,s) in C_of_K]
# Sage doesn't think matrices are vectors, so we have to convert
# our matrices to vectors explicitly before we can figure out how